Area of Parallelograms and Trapeziums

In a Nutshell

A parallelogram has the same area as a rectangle with the same base and height. A trapezium's area uses the average of its two parallel sides multiplied by its height.

Area of a parallelogram

If you cut a triangle off one end of a parallelogram and move it to the other end, you make a rectangle. That is why:

Area of parallelogram=b×h\text{Area of parallelogram} = b \times h

Here bb is the base and hh is the perpendicular height — not the slant height.

Area of a trapezium

A trapezium has one pair of parallel sides, labelled aa (top) and bb (bottom). Its area formula is:

Area of trapezium=12(a+b)×h\text{Area of trapezium} = \frac{1}{2}(a + b) \times h

Think of it as: find the average of the two parallel sides, then multiply by the height. This works because two identical trapeziums fit together to make a parallelogram of base (a+b)(a + b).

See it: rearrange into a rectangle

Parallelogram to rectangle transformation Watch a triangle slice off one end of a parallelogram and slide across to form a rectangle, proving that Area equals base times height.
Shape:

Choose Parallelogram and press Transform to watch a triangle slice off one end and slide across, forming a rectangle. Use the slant slider to try different shapes — the trick always works. Switch to Trapezium to see how two copies fit together into a rectangle of width (a + b).

Watch it work

Question: Find the area of a trapezium with parallel sides a=6cma = 6 \, \text{cm} and b=10cmb = 10 \, \text{cm}, and height h=4cmh = 4 \, \text{cm}.

Have a go

Q1. Find the area of a parallelogram with base 9cm9 \, \text{cm} and perpendicular height 5cm5 \, \text{cm}.

Q2. Find the area of a trapezium with a=5cma = 5 \, \text{cm}, b=9cmb = 9 \, \text{cm} and h=6cmh = 6 \, \text{cm}.

Q3. A parallelogram has area 72cm272 \, \text{cm}^2 and base 8cm8 \, \text{cm}. Find its height.

Q4. Find the area of a trapezium with parallel sides 4cm4 \, \text{cm} and 8cm8 \, \text{cm}, and height 5cm5 \, \text{cm}.